New Delhi: Rohit Sharma became the second highest run-getter in 2018 during the fifth One-Day International (ODI) against West Indies at Greenfield International Stadium in Thiruvananthapuram on Thursday.
Sharma (1,030 runs) broke the record of England batsman Jonny Bairstow (1,025) to take the second spot behind his national team skipper Virat Kohli.
The 31-year-old achieved the feat in 19 matches and identical number of innings. He averages 73.57 in 2018, with the highest score of 162 runs.
The right-handed batsman also crossed the 200-sixes mark breaking the record of Pakistani batsman Shahid Afridi. Afridi completed his 200 sixes mark in 195 innings, while Sharma achieved the milestone in the second six of his 187th inning. He became the second quickest Indian batsman after MS Dhoni who scored 218 sixes in a total of 281 innings. Earlier, Rohit had beaten Sachin Tendulkar’s tally of 195 sixes in the 4th ODI.
Indian run-machine, Virat Kohli has scored 1,202 runs in the 50-over format with the highest score of an unbeaten 160. He averages a staggering 133.55 in this calendar year.
India defeated West Indies by nine wickets in the final One-day International to win the five-match series 3-1 in Thiruvananthapuram on Thursday.
Rohit will be next seen in action during the three-match Twenty20 International (T20I) series against the Windies, starting from November 4 at the Eden Gardens in Kolkata. He will lead the home team in absence of the regular skipper Kohli.